Use the divisibility rules to find multiples of 3
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I know the divisibility rule for multiples of 3 and can use it with 3- and 4-digit numbers.
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Numbers that can be divided by 3 and leave no remainder are divisible by 3
To find the digit sum of a number, add the digits in the number together so the digit sum of 17 is 1 + 7 which equals 8
For a number to be divisible by three, the dgit sum of the number must be a divisible by 3
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