Solve problems using divisibility rules for divisors of 3, 6 and 9
Lesson 5 / 5
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I can solve problems using divisibility rules for divisors of 3 and 6
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For a number to be divisible by three, the dgit sum of the number must be a divisible by 3
For a number to be divisible by 6, it must be divisible by both 2 and 3
If you halve a number and the digit sum of the half is a multiple of 3 then the number is divisible by 6
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