Interpreting I–V graphs
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I can take readings from I–V graphs and use these to describe the changing resistance of a component.
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In forward–bias, a diode has a very small resistance when the p.d. is larger than the threshold voltage.
In reverse–bias, a diode has a very large resistance and very little current can flow.
The greater the p.d. across a component, the larger the push on electric charges in the component.
The resistance of a component is calculated from an I–V graph using pairs of readings and the equation R = V ÷ I.
The greater the current through a component, the larger the heating effect on it.
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